Recently, the smartphone manufacturer ZTE launched it’s latest high-end device ZTE Nubia M2 in India. Now the newly device ZTE V0840 spotted on Geekbench listing and revealed that the device will come with 3GB RAM, it will be powered by Snapdragon 425 SoC chipset and runs on Android 7.1.1 Nougat. Since, the device already showed its presence on TENAA and unveiled that it will feature a 5-inch HD display 16GB/32GB storage options, 8MP dual rear camera, and a front-facing camera of 5MP.It will be powered by a 2,500mAh battery. The cost of the device ZTE V0840 and its availability is still unconfirmed yet.
The device ZTE Nubia M2 sports a 5.5-inch 1080p Full HD AMOLED display, 4GB RAM, internal storage capacity of 64GB, which can be further expanded up to 200GB via microSD card slot. It is powered by 2GHz Octa-Core Snapdragon 625 14nm processor with Adreno 506 GPU and runs on Android 6.0.1 Marshmallow. It comes with a fingerprint sensor placed on its physical Home button. It has the dimension of 154.5×75.9×7mm and weighs 168g.
It packs a dual rear camera setup including a dual 13 MP sensors, one color, one monochrome. Both are protected by sapphire, and both come with f/2.2 aperture. It has a front-facing camera of 16MP with f/2.0 aperture and an 80-degree field of view.
Connectivity wise, it includes 4G LTE, Wi-Fi, Bluetooth, GPS, GLONASS, and a USB Type-C port and supports TAS2555 Amplifier, 7.1 channel Dolby audio, Hi-Fi audio. It is powered by a 3,630 mAh battery with support for fast charging.
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